2016719ensp 0183enspA farmer wants to fence in 60,000 square feet of land in a rectangular plot along a straight highway. The fence he plans to use along the highway costs 2 per foot, while the fence for the other three sides costs 1 per foot. How much of each type of fence will he have to buy in order to keep expenses to a minimum【Get Price】

2016719ensp 0183enspCost of Fencing for a Field By Leighton McIntyre Goal: To find the minimum cost of fencing given different costs Problem A farmer wants to fence in 60,000 square feet of land in a rectangular plot along a straight highway. The fence he plans to use along the highway costs 2 per foot, while the fence for the other three sides costs 1 per foot.: 90KB【Get Price】

A farmer wants to fence an area of 60,000 m2 in a rectangular field and then divide it in half with a fence parallel to one of the sides of the rectangle. Let y represent the length in meters of a side perpendicular to the dividing fence, and let x represent the length in meters of a side parallel to the dividing fence.【Get Price】

20131111ensp 0183enspA farmer wants to fence an area of 6 million square feet in a rectangular field and then divide it in half with a fence parallel to one of the sides of the rectangle. What should the lengths of the sides of the rectangular field be so as to minimize the cost of the fence Given: Area displaystyle A lw displaystyle 6,000,000 lw 【Get Price】

201032ensp 0183enspA farmer wants to fence an area of 6 million square feet in a rectangular field and then divide it in half with a fence parallel to one of the sides of the rectangle. What should the lengths of the sides of the rectangular field . Algebra. Farmer Ed has 9,000 meters of fencing, and wants to enclose a rectangular plot that borders on a river. ...【Get Price】

:A farmer wants to fence an area of 6 million square feet in a rectangular field and then divide it in half with a fence parallel to one of the sides of the rectangle. How can he do this so as to minimize the c:If the rectangular field has notional sides x and y, then it has area: The length of fencing required, if x is the letter that was arbitrarily assigned to the side to which the dividing fence runsocratic.org【Get Price】

A farmer wants to fence in a rectangular plot of land adjacent to the north wall of his barn. No fencing is needed along the barn, and the fencing along the west side of the plot is shared with a neighbor who will split the cost of that portion of the fence. If the fencing costs 24 per linear foot to install and the farmer 【Get Price】

2011118ensp 0183enspA farmer wants to fence an area of 1.5 million square feet in a rectangular field and then divide it in half with a fence parallel to one of the sides of the rectangle. How can he do this so as to minimize the cost of the fence i know one of my equations is Axy1500000 but other than that i...【Get Price】

A farmer wants to fence in an area of 1.5 million square feet in a rectangular field and then divide it in half with a fence parallel to one of the sides of ...【Get Price】

2019101ensp 0183enspA farmer wants to fence a small rectangular yard next to a barn. Fence for side parallel to the barn will cost 75 per foot and the fence for the other two sides will cost 30 per foot. The farmer has a total of 1750 dollars to . clemson. A farmer wants to make three identical rectangular enclosures along a straight river, as in the diagram shown ...【Get Price】

2018617ensp 0183enspIf the rectangular field has notional sides x and y , then it has area:. A bbx xy qquad 610^6 quot sq ftquot The length of fencing required, if x is the letter that was arbitrarily assigned to the side to which the dividing fence runs parallel, is:. L bbx 3x 2y It matters not that the farmer wishes to divide the area into 2 exact smaller areas.【Get Price】

2019419ensp 0183enspA farmer wants to fence in a rectangular plot of land adjacent to the north wall of his barn. No fencing is needed along the barn, and the fencing along the west side of the plot is shared with a neighbor who will split the cost of that portion of the fence. If the fencing costs 10 per linear foot to install and the farmer is not willing to ...【Get Price】

A farmer wants to fence in an area of 1.5 million square feet in a rectangular field and then divide it in half with a fence parallel to one of the sides of the rectangle. How can he do this so as to minimize the cost of the fence close. Start your trial now First week only 4.99 arrow forward.【Get Price】

2021103ensp 0183enspA farmer wants to fence an area of 1.5 million square feet in a rectangular field and then divide it in half with a fence parallel to one of the sides. How can he do this so as to minimize the cost of the fence I know that my two functions are【Get Price】

Find stepbystep Calculus solutions and your answer to the following textbook question: A farmer wants to fence an area of 1.5 million square feet in a rectangular field and then divide it in half with a fence parallel to one of the sides of the rectangle. How can he do this so as to minimize the cost of the fence.【Get Price】

Answer 1 of 5 : Begin by drawing a picture of the problem. Label the sides of the plot that will be fenced. The sides to be fenced are 2 widths each of length x meters and a length of 65002x meters. You want to find the largest value for Area, which means you will need an equation for Area of ...【Get Price】

Question 159089: A farmer with 10,000 meters of fencing wants to enclose a rectangular field and then divide it into three plots with two fences parallel to one of the sides. What is the area that can be enclosed I need to find the vertex but cannot figure out how to solve this problem. Analyzing Graphs of Quadratic Functions .【Get Price】

20161230ensp 0183enspA farmer wants to enclose a 450,000m^2 rectangular field with fence. She then wants to subdivide this field into three smaller fields by placing additional lengths of fence parallel to one of the side. How can she do this so that she minimizes the cost My equations are 450,000xy and P6x 4y, where x is the width and y is the length. ...【Get Price】

Answer 1 of 6 : Ok, so we have 4 sides. One of which we do not have to care about. Since we want a rectangle, 2 of the remaining sides will be of the same length, lets call that length x. The remaining side can therefore only have length 10002x, since the other two sides eats up some fence...【Get Price】

200878ensp 0183enspLets define some variables. Well call the length L, and the width W. Then we can express the above algebraically:300 perimeter 2L 2W3600 area L x WNow lets find one variable in terms of the other:300 2L 2W300 2W 2L 300 2W /2 LSince we now have the length in terms of width, we can substitute for L in the second equation:3600 L x W3600 300 2W /2 x W3600 300W ...【Get Price】

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